Good morning. Let's start now. It's time. And because I didn't have all solutions to
the task, I will explain how to solve it in the end of the lecture. Hopefully some people
are late. And hopefully I will get the solutions later. So we started the subject that is called
quantization of the electromagnetic field. But in fact, I just derived based on the Maxwell's
equations, I derived the equation for the single field component. I will remind you
that we obtained the field as a function of coordinate and time in the form of a Fourier
series over harmonics k. And here stood k's harmonics as a function of time only. And
the spatial dependence was written like this. I, k, r are the exponent. And it means that
the all spatial dependence is here and the time dependence is here. The same equation
we got for the magnetic field, b, k. I will not write it explicitly. Thank you. But the
important thing is that we got the oscillator equation for this e, k of t. I will meet vectors
here. We will not be using vectors. Further on, for the time dependence, for the amplitude
of the electric field, we got the equation e, k of t, two dots, meaning the time derivative,
double time derivative plus omega k squared e, k of t is 0. And the solution, of course,
we wrote that e, k of t is 1 half. And here, two terms there, negative frequency and the
positive frequency, e, k naught, e minus i omega k t, and plus e, k naught complex conjugated,
e i omega k t. I forgot to mention probably that because of this representation, this
representation, because the field is a real value, then its Fourier component satisfies
a certain rule, and namely, this e, k of t, if we take it complex conjugated, it will
be equal to e minus k of t. Because of the field being real, because of this being the
Fourier expansion, serious expansion. Then from this dependence of the field, we can
find the dependence on time of the magnetic field. And for this, we need to use some of
the Maxwell's equations that we wrote before, namely, I'll just write it here. So the Maxwell's
equation that we needed was nabla times b minus 1 over c squared e dot is 0. So this
equation we wrote in the previous lecture. And to find the magnetic field, I apply this
equation to the harmonic, to each harmonic of the magnetic field. So we have nabla times
b k will be 1 over c squared e k dot. And then we know that the nabla operator, if the
field has such dependence on space, is just plus i k vector times the b k component. So
far I write vectors because I need to explain how this vector product looks, which is 1
over c squared i k vector e k derivative. But then if we imagine the situation, so this
is, for instance, the k vector. And this, for instance, is the b magnetic field, b k
component. Then this vector product creates a vector directed, so we have to rotate from
k to b. And so it creates a vector in this direction. So this is k times b k. And then
what I do next, I will multiply it. Sorry, this is wrong. Why did I write it here? It's
just a derivative. And then I multiply it again by k vector. And so what happens if
I multiply the vector product of k and b by k again? So so far we got a vector sticking
out of the blackboard. And then this vector I multiply by k again. And this gives me again
the vector b k, but with a minus sign. So I had a vector sticking out. And then I multiply
it by k vector. I have a vector. So this k times k times b k, this is the vector, is
just minus k squared because I have this number. And then I have a vector parallel to b k.
So I will have a b k direction over b k. So I have the same value, just multiplied by
k squared and with a minus sign because of these directions of rotation. It means that
here I will obtain i, the minus, and then k squared. And then b k is 1 over c squared.
And here because I multiplied by k, I have to write it here. Here. And from this, Alice
Clarke or Dunn-Yt? Sorry?
b k in the expression should be normal.
No, no, no, no. Yeah, yeah, yeah, yeah, yeah, yeah, right, right, right here. Yeah, yeah,
yeah, yeah, yeah. So from this equation, I can derive b k. So b k. And now I will omit
the indices. Sorry, no, let me write the vectors. So b k vector is now i goes to the numerator,
c squared denominator. And then there is the wave vector k, k squared. And then e k vector
Presenters
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Dauer
01:33:36 Min
Aufnahmedatum
2019-11-21
Hochgeladen am
2019-11-25 13:11:59
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en-US