Okay, hello. We are just discussing some ways of producing Schrodinger cats and we were
just discussing optomechanics that is light and acting with mechanical motion which could
give rise to a Schrodinger cat state in principle so I'll just draw the setup again. So we have
an optical cavity but one of the mirrors can actually vibrate for example because of the
tension to a sun cantilever and so if a laser shines into the cavity and light circulates
inside the cavity there will be a radiation pressure force proportional to the intensity,
proportional to the energy of light stored inside the cavity. And so when we discuss
measurement we already discussed how this could be used to measure the motion of the
mechanical oscillator via the phase shift of the right beam for example but now we are
also discussing the fact that since the force depends on the energy stored inside the cavity
we can actually entangle the optical field and the mechanical motion. And the simplest
version of that idea would be to imagine you have a coherent superposition of many different
photon numbers, each photon number gives rise to a different radiation pressure force
so after some while you will end up in an entangled state where different photon numbers
are associated with different motion of the cantilever. So now I wanted to talk a bit
about decoherence in such a setup. For example imagine you have created a state involving
a superposition of 1 and 0 phonons, this is the most modest kind of cat we can think of
of course if you are more ambitious you will involve more phonons. Now how to calculate
the decoherence rate in such a case where if this is the harmonic oscillator potential
for my mechanical motion then these are the energy levels of the harmonic oscillator,
if it is in its round state then there are zero phonons, if it is in the first excited
state we say there is exactly one phonon and so on. So now imagine we have placed it for
example in a superposition of state number 0 and state number 1 then obviously this superposition
can be destroyed for the simple fact that because of the damping of the mechanical motion
the system can relax down to the ground state. Also if the system is actually at some fire
temperature T so there are always these thermal vibrations in the substrate to which the cantilever
is coupled then once in a while a thermal phonon, a thermal vibration will go into the
cantilever and excite its motion. So in that case we also have a rate that takes us up
from the ground state to the first excited state but nevertheless since this is a thermal
phonon which is completely incoherent it would also destroy the superposition. So these are
the bad processes. Now what is the rate for example to go down from 1 to 0? Well it turns
out of course this rate is connected to the damping rate and at 0 temperature that would
be everything but if we are at a finer temperature then in addition to this spontaneous emission
given by the rate gamma we also could have some thermally induced emission because there
is a finite number of thermal phonons. So this rate actually gets multiplied with n
thermal plus 1 and n thermal is really the occupation of the environment at this particular
frequency, the frequency of the cantilever mode called omega and also given by the temperature
so that would be given by the Bose Einstein distribution. So this makes things worse at
higher temperatures and if you ask me okay what is the corresponding rate to go up from
0 to 1? This is also given by gamma as a pre-factor but then we can only absorb thermal phonons
so that would only be given by n thermal and if the environment were at 0 temperature which
usually it is not in these experiments then this rate would completely vanish and likewise
there are ways for example taking rules. So if I then want to have an estimate for my
decoherence rate for such a situation where I am in a superposition of maybe the first
few excited states then it is really given by this gamma times n thermal maybe plus 1
but now I would imagine a situation where the temperature is much higher than the h
bar omega so that n thermal really over worms this extra factor of 1. So then I would allow
myself to just define gamma by this gamma times n thermal and in any given situation
that you want to describe you better solve the master equation to really find out for
your particular state what is the effective rate at which it decays but this sets the
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01:30:15 Min
Aufnahmedatum
2013-06-14
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2013-09-02 11:43:18
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